(x-3)/x=2/(x+4)

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Solution for (x-3)/x=2/(x+4) equation: 



(x-3)/x=2/(x+4)

We move all terms to the left:

(x-3)/x-(2/(x+4))=0



Domain of the equation: x!=0

x∈R





Domain of the equation: (x+4))!=0

x∈R



We calculate fractions


((x-3)*(x+4)))/5x^2+(-(2*x)/5x^2=0

We add all the numbers together, and all the variables

((x-3)*(x+4)))/5x^2+(-(+2x)/5x^2=0

We calculate fractions


(((x-3)*(x+4)))*5x^2)/(5x^2+(*5x^2)+(-(+2x)*5x^2)/(5x^2+(*5x^2)=0



We calculate terms in parentheses: +(-(+2x)*5x^2)/(5x^2+(*5x^2), so:

-(+2x)*5x^2)/(5x^2+(*5x^2

We multiply all the terms by the denominator


-(+2x)*5x^2)+((*5x^2)*(5x^2

Back to the equation:

+(-(+2x)*5x^2)+((*5x^2)*(5x^2)



We get rid of parentheses

(((x-3)*(x+4)))*5x^2)/(5x^2+*5x^2+(-(+2x)*5x^2)+((*5x^2)*5x^2=0

We multiply all the terms by the denominator


(((x-3)*(x+4)))*5x^2)+(*5x^2)*(5x^2+((-(+2x)*5x^2))*(5x^2+(((*5x^2)*5x^2)*(5x^2=0

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