(x-3)2+(y+3)2=64

Solution for (x-3)2+(y+3)2=64 equation:

Simplifying
(x + -3) * 2 + (y + 3) * 2 = 64

Reorder the terms:
(-3 + x) * 2 + (y + 3) * 2 = 64

Reorder the terms for easier multiplication:
2(-3 + x) + (y + 3) * 2 = 64
(-3 * 2 + x * 2) + (y + 3) * 2 = 64
(-6 + 2x) + (y + 3) * 2 = 64

Reorder the terms:
-6 + 2x + (3 + y) * 2 = 64

Reorder the terms for easier multiplication:
-6 + 2x + 2(3 + y) = 64
-6 + 2x + (3 * 2 + y * 2) = 64
-6 + 2x + (6 + 2y) = 64

Reorder the terms:
-6 + 6 + 2x + 2y = 64

Combine like terms: -6 + 6 = 0
0 + 2x + 2y = 64
2x + 2y = 64

Solving
2x + 2y = 64

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2y' to each side of the equation.
2x + 2y + -2y = 64 + -2y

Combine like terms: 2y + -2y = 0
2x + 0 = 64 + -2y
2x = 64 + -2y

Divide each side by '2'.
x = 32 + -1y

Simplifying
x = 32 + -1y