(x-3)2+(y-5)2=20

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Solution for (x-3)2+(y-5)2=20 equation:


Simplifying
(x + -3) * 2 + (y + -5) * 2 = 20

Reorder the terms:
(-3 + x) * 2 + (y + -5) * 2 = 20

Reorder the terms for easier multiplication:
2(-3 + x) + (y + -5) * 2 = 20
(-3 * 2 + x * 2) + (y + -5) * 2 = 20
(-6 + 2x) + (y + -5) * 2 = 20

Reorder the terms:
-6 + 2x + (-5 + y) * 2 = 20

Reorder the terms for easier multiplication:
-6 + 2x + 2(-5 + y) = 20
-6 + 2x + (-5 * 2 + y * 2) = 20
-6 + 2x + (-10 + 2y) = 20

Reorder the terms:
-6 + -10 + 2x + 2y = 20

Combine like terms: -6 + -10 = -16
-16 + 2x + 2y = 20

Solving
-16 + 2x + 2y = 20

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '16' to each side of the equation.
-16 + 2x + 16 + 2y = 20 + 16

Reorder the terms:
-16 + 16 + 2x + 2y = 20 + 16

Combine like terms: -16 + 16 = 0
0 + 2x + 2y = 20 + 16
2x + 2y = 20 + 16

Combine like terms: 20 + 16 = 36
2x + 2y = 36

Add '-2y' to each side of the equation.
2x + 2y + -2y = 36 + -2y

Combine like terms: 2y + -2y = 0
2x + 0 = 36 + -2y
2x = 36 + -2y

Divide each side by '2'.
x = 18 + -1y

Simplifying
x = 18 + -1y

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