(x-3)2-(x+3)2=x2

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Solution for (x-3)2-(x+3)2=x2 equation: 



(x-3)2-(x+3)2=x2

We move all terms to the left:

(x-3)2-(x+3)2-(x2)=0

We add all the numbers together, and all the variables

-1x^2+(x-3)2-(x+3)2=0

We multiply parentheses

-1x^2+2x-2x-6-6=0

We add all the numbers together, and all the variables

-1x^2-12=0

a = -1; b = 0; c = -12;
Δ = b2-4ac
Δ = 02-4·(-1)·(-12)
Δ = -48
Delta is less than zero, so there is no solution for the equation

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