(x-3)5+7=(2x+1)/3

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Solution for (x-3)5+7=(2x+1)/3 equation:



(x-3)5+7=(2x+1)/3
We move all terms to the left:
(x-3)5+7-((2x+1)/3)=0
We multiply parentheses
5x-((2x+1)/3)-15+7=0
We multiply all the terms by the denominator
5x*3)-((2x+1)-15*3)+7*3)=0
We add all the numbers together, and all the variables
5x*3)-((2x+1)=0
Wy multiply elements
15x^2=0
a = 15; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·15·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{30}=0$

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