(x-3)8x-(x+3)(x-3)8=(x+3)(x-39-)

Solution for (x-3)8x-(x+3)(x-3)8=(x+3)(x-39-) equation:

(x-3)8x-(x+3)(x-3)8=(x+3)(x-39-)

We move all terms to the left:

(x-3)8x-(x+3)(x-3)8-((x+3)(x-39-))=0

We add all the numbers together, and all the variables

(x-3)8x-(x+3)(x-3)8-((x+3)(+x))=0

We use the square of the difference formula

x^2+(x-3)8x-((x+3)(+x))+9=0

We multiply parentheses

x^2+8x^2-24x-((x+3)(+x))+9=0

We multiply parentheses ..

x^2+8x^2-((+x^2+3x))-24x+9=0


We calculate terms in parentheses: -((+x^2+3x)), so:

(+x^2+3x)

We get rid of parentheses

x^2+3x

Back to the equation:

-(x^2+3x)


We add all the numbers together, and all the variables

9x^2-24x-(x^2+3x)+9=0

We get rid of parentheses

9x^2-x^2-24x-3x+9=0

We add all the numbers together, and all the variables

8x^2-27x+9=0

a = 8; b = -27; c = +9;
Δ = b2-4ac
Δ = -272-4·8·9
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{441}=21$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-21}{2*8}=\frac{6}{16}
=3/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+21}{2*8}=\frac{48}{16}
=3
$