(x-3)=(x-2)(x-2)

Solution for (x-3)=(x-2)(x-2) equation:

(x-3)=(x-2)(x-2)

We move all terms to the left:

(x-3)-((x-2)(x-2))=0

We get rid of parentheses

x-((x-2)(x-2))-3=0

We multiply parentheses ..

-((+x^2-2x-2x+4))+x-3=0


We calculate terms in parentheses: -((+x^2-2x-2x+4)), so:

(+x^2-2x-2x+4)

We get rid of parentheses

x^2-2x-2x+4

We add all the numbers together, and all the variables

x^2-4x+4

Back to the equation:

-(x^2-4x+4)


We add all the numbers together, and all the variables

x-(x^2-4x+4)-3=0

We get rid of parentheses

-x^2+x+4x-4-3=0

We add all the numbers together, and all the variables

-1x^2+5x-7=0

a = -1; b = 5; c = -7;
Δ = b2-4ac
Δ = 52-4·(-1)·(-7)
Δ = -3
Delta is less than zero, so there is no solution for the equation