(x-3)=x(x-5)

Solution for (x-3)=x(x-5) equation:

(x-3)=x(x-5)

We move all terms to the left:

(x-3)-(x(x-5))=0

We get rid of parentheses

x-(x(x-5))-3=0


We calculate terms in parentheses: -(x(x-5)), so:

x(x-5)

We multiply parentheses

x^2-5x

Back to the equation:

-(x^2-5x)


We get rid of parentheses

-x^2+x+5x-3=0

We add all the numbers together, and all the variables

-1x^2+6x-3=0

a = -1; b = 6; c = -3;
Δ = b2-4ac
Δ = 62-4·(-1)·(-3)
Δ = 24
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{24}=\sqrt{4*6}=\sqrt{4}*\sqrt{6}=2\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{6}}{2*-1}=\frac{-6-2\sqrt{6}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{6}}{2*-1}=\frac{-6+2\sqrt{6}}{-2}
$