(x-3)=x+(3x-1)+x-5=87

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Solution for (x-3)=x+(3x-1)+x-5=87 equation: 



(x-3)=x+(3x-1)+x-5=87

We move all terms to the left:

(x-3)-(x+(3x-1)+x-5)=0

We get rid of parentheses

x-(x+(3x-1)+x-5)-3=0



We calculate terms in parentheses: -(x+(3x-1)+x-5), so:

x+(3x-1)+x-5

We add all the numbers together, and all the variables

2x+(3x-1)-5

We get rid of parentheses

2x+3x-1-5

We add all the numbers together, and all the variables

5x-6

Back to the equation:

-(5x-6)



We get rid of parentheses

x-5x+6-3=0

We add all the numbers together, and all the variables

-4x+3=0

We move all terms containing x to the left, all other terms to the right

-4x=-3

x=-3/-4

x=3/4

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