(x-3/2)2-5/4=0

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Solution for (x-3/2)2-5/4=0 equation: 


x in (-oo:+oo)

(x-(3/2))^2-(5/4) = 0

(x-3/2)^2-5/4 = 0

(4*(x-3/2)^2)/4-5/4 = 0

4*(x-3/2)^2-5 = 0

4*x^2-12*x+4 = 0

4*x^2-12*x+4 = 0

4*(x^2-3*x+1) = 0

x^2-3*x+1 = 0

DELTA = (-3)^2-(1*1*4)

DELTA = 5

DELTA > 0

x = (5^(1/2)+3)/(1*2) or x = (3-5^(1/2))/(1*2)

x = (5^(1/2)+3)/2 or x = (3-5^(1/2))/2

4*(x-((3-5^(1/2))/2))*(x-((5^(1/2)+3)/2)) = 0

(4*(x-((3-5^(1/2))/2))*(x-((5^(1/2)+3)/2)))/4 = 0

(4*(x-((3-5^(1/2))/2))*(x-((5^(1/2)+3)/2)))/4 = 0 // * 4

4*(x-((3-5^(1/2))/2))*(x-((5^(1/2)+3)/2)) = 0

( 4 )

4 = 0

x belongs to the empty set

( x-((3-5^(1/2))/2) )

x-((3-5^(1/2))/2) = 0 // + (3-5^(1/2))/2

x = (3-5^(1/2))/2

( x-((5^(1/2)+3)/2) )

x-((5^(1/2)+3)/2) = 0 // + (5^(1/2)+3)/2

x = (5^(1/2)+3)/2

x in { (3-5^(1/2))/2, (5^(1/2)+3)/2 }

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