(x-3i)(x+3i)=

Solution for (x-3i)(x+3i)= equation:

Simplifying
(x + -3i)(x + 3i) = 0

Reorder the terms:
(-3i + x)(x + 3i) = 0

Reorder the terms:
(-3i + x)(3i + x) = 0

Multiply (-3i + x) * (3i + x)
(-3i * (3i + x) + x(3i + x)) = 0
((3i * -3i + x * -3i) + x(3i + x)) = 0

Reorder the terms:
((-3ix + -9i2) + x(3i + x)) = 0
((-3ix + -9i2) + x(3i + x)) = 0
(-3ix + -9i2 + (3i * x + x * x)) = 0
(-3ix + -9i2 + (3ix + x2)) = 0

Reorder the terms:
(-3ix + 3ix + -9i2 + x2) = 0

Combine like terms: -3ix + 3ix = 0
(0 + -9i2 + x2) = 0
(-9i2 + x2) = 0

Solving
-9i2 + x2 = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-1x2' to each side of the equation.
-9i2 + x2 + -1x2 = 0 + -1x2

Combine like terms: x2 + -1x2 = 0
-9i2 + 0 = 0 + -1x2
-9i2 = 0 + -1x2
Remove the zero:
-9i2 = -1x2

Divide each side by '-9'.
i2 = 0.1111111111x2

Simplifying
i2 = 0.1111111111x2

Take the square root of each side:
i = {-0.333333333x, 0.333333333x}