(x-3y)(x+3y)=

Solution for (x-3y)(x+3y)= equation:

Simplifying
(x + -3y)(x + 3y) = 0

Multiply (x + -3y) * (x + 3y)
(x(x + 3y) + -3y * (x + 3y)) = 0
((x * x + 3y * x) + -3y * (x + 3y)) = 0

Reorder the terms:
((3xy + x2) + -3y * (x + 3y)) = 0
((3xy + x2) + -3y * (x + 3y)) = 0
(3xy + x2 + (x * -3y + 3y * -3y)) = 0
(3xy + x2 + (-3xy + -9y2)) = 0

Reorder the terms:
(3xy + -3xy + x2 + -9y2) = 0

Combine like terms: 3xy + -3xy = 0
(0 + x2 + -9y2) = 0
(x2 + -9y2) = 0

Solving
x2 + -9y2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '9y2' to each side of the equation.
x2 + -9y2 + 9y2 = 0 + 9y2

Combine like terms: -9y2 + 9y2 = 0
x2 + 0 = 0 + 9y2
x2 = 0 + 9y2
Remove the zero:
x2 = 9y2

Simplifying
x2 = 9y2

Take the square root of each side:
x = {-3y, 3y}