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(x-4)(3x+6)(5-10x)(3x+6)=6x+12
We move all terms to the left:
(x-4)(3x+6)(5-10x)(3x+6)-(6x+12)=0
We add all the numbers together, and all the variables
(x-4)(3x+6)(-10x+5)(3x+6)-(6x+12)=0
We get rid of parentheses
(x-4)(3x+6)(-10x+5)(3x+6)-6x-12=0
We multiply parentheses ..
(+3x^2+6x-12x-24)(-10x+5)(3x+6)-6x-12=0
We multiply parentheses ..
(+3x^2+6x-12x-24)(-30x^2-60x+15x+30)-6x-12=0
We move all terms containing x to the left, all other terms to the right
(+3x^2+6x-12x-24)(-30x^2-60x+15x+30)-6x=12
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