(x-4)(4-x)=15

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Solution for (x-4)(4-x)=15 equation: 



(x-4)(4-x)=15

We move all terms to the left:

(x-4)(4-x)-(15)=0

We add all the numbers together, and all the variables

(x-4)(-1x+4)-15=0

We multiply parentheses ..

(-1x^2+4x+4x-16)-15=0

We get rid of parentheses

-1x^2+4x+4x-16-15=0

We add all the numbers together, and all the variables

-1x^2+8x-31=0

a = -1; b = 8; c = -31;
Δ = b2-4ac
Δ = 82-4·(-1)·(-31)
Δ = -60
Delta is less than zero, so there is no solution for the equation

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