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(x-4)(4x+20)=0
We multiply parentheses ..
(+4x^2+20x-16x-80)=0
We get rid of parentheses
4x^2+20x-16x-80=0
We add all the numbers together, and all the variables
4x^2+4x-80=0
a = 4; b = 4; c = -80;
Δ = b2-4ac
Δ = 42-4·4·(-80)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1296}=36$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-36}{2*4}=\frac{-40}{8} =-5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+36}{2*4}=\frac{32}{8} =4 $
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