(x-4)(7-x)=5-x2

Solution for (x-4)(7-x)=5-x2 equation:

(x-4)(7-x)=5-x2

We move all terms to the left:

(x-4)(7-x)-(5-x2)=0

We add all the numbers together, and all the variables

-(-1x^2+5)+(x-4)(-1x+7)=0

We get rid of parentheses

1x^2+(x-4)(-1x+7)-5=0

We multiply parentheses ..

1x^2+(-1x^2+7x+4x-28)-5=0

We add all the numbers together, and all the variables

x^2+(-1x^2+7x+4x-28)-5=0

We get rid of parentheses

x^2-1x^2+7x+4x-28-5=0

We add all the numbers together, and all the variables

11x-33=0

We move all terms containing x to the left, all other terms to the right

11x=33

x=33/11

x=3