(x-4)(x+1)-(x+7)(x+3)=-7x+17

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Solution for (x-4)(x+1)-(x+7)(x+3)=-7x+17 equation: 



(x-4)(x+1)-(x+7)(x+3)=-7x+17

We move all terms to the left:

(x-4)(x+1)-(x+7)(x+3)-(-7x+17)=0

We get rid of parentheses

(x-4)(x+1)-(x+7)(x+3)+7x-17=0

We multiply parentheses ..

(+x^2+x-4x-4)-(x+7)(x+3)+7x-17=0

We add all the numbers together, and all the variables

(+x^2+x-4x-4)+7x-(x+7)(x+3)-17=0

We get rid of parentheses

x^2+x-4x+7x-(x+7)(x+3)-4-17=0

We multiply parentheses ..

x^2-(+x^2+3x+7x+21)+x-4x+7x-4-17=0

We add all the numbers together, and all the variables

x^2-(+x^2+3x+7x+21)+4x-21=0

We get rid of parentheses

x^2-x^2-3x-7x+4x-21-21=0

We add all the numbers together, and all the variables

-6x-42=0

We move all terms containing x to the left, all other terms to the right

-6x=42

x=42/-6

x=-7

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