(x-4)(x+2)(x+2)=0

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Solution for (x-4)(x+2)(x+2)=0 equation:


Simplifying
(x + -4)(x + 2)(x + 2) = 0

Reorder the terms:
(-4 + x)(x + 2)(x + 2) = 0

Reorder the terms:
(-4 + x)(2 + x)(x + 2) = 0

Reorder the terms:
(-4 + x)(2 + x)(2 + x) = 0

Multiply (-4 + x) * (2 + x)
(-4(2 + x) + x(2 + x))(2 + x) = 0
((2 * -4 + x * -4) + x(2 + x))(2 + x) = 0
((-8 + -4x) + x(2 + x))(2 + x) = 0
(-8 + -4x + (2 * x + x * x))(2 + x) = 0
(-8 + -4x + (2x + x2))(2 + x) = 0

Combine like terms: -4x + 2x = -2x
(-8 + -2x + x2)(2 + x) = 0

Multiply (-8 + -2x + x2) * (2 + x)
(-8(2 + x) + -2x * (2 + x) + x2(2 + x)) = 0
((2 * -8 + x * -8) + -2x * (2 + x) + x2(2 + x)) = 0
((-16 + -8x) + -2x * (2 + x) + x2(2 + x)) = 0
(-16 + -8x + (2 * -2x + x * -2x) + x2(2 + x)) = 0
(-16 + -8x + (-4x + -2x2) + x2(2 + x)) = 0
(-16 + -8x + -4x + -2x2 + (2 * x2 + x * x2)) = 0
(-16 + -8x + -4x + -2x2 + (2x2 + x3)) = 0

Combine like terms: -8x + -4x = -12x
(-16 + -12x + -2x2 + 2x2 + x3) = 0

Combine like terms: -2x2 + 2x2 = 0
(-16 + -12x + 0 + x3) = 0
(-16 + -12x + x3) = 0

Solving
-16 + -12x + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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