(x-4)(x+2)-(x-5)(x+6)=-x

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Solution for (x-4)(x+2)-(x-5)(x+6)=-x equation: 



(x-4)(x+2)-(x-5)(x+6)=-x

We move all terms to the left:

(x-4)(x+2)-(x-5)(x+6)-(-x)=0

We add all the numbers together, and all the variables

(x-4)(x+2)-(x-5)(x+6)-(-1x)=0

We get rid of parentheses

(x-4)(x+2)-(x-5)(x+6)+1x=0

We multiply parentheses ..

(+x^2+2x-4x-8)-(x-5)(x+6)+1x=0

We add all the numbers together, and all the variables

(+x^2+2x-4x-8)+x-(x-5)(x+6)=0

We get rid of parentheses

x^2+2x-4x+x-(x-5)(x+6)-8=0

We multiply parentheses ..

x^2-(+x^2+6x-5x-30)+2x-4x+x-8=0

We add all the numbers together, and all the variables

x^2-(+x^2+6x-5x-30)-1x-8=0

We get rid of parentheses

x^2-x^2-6x+5x-1x+30-8=0

We add all the numbers together, and all the variables

-2x+22=0

We move all terms containing x to the left, all other terms to the right

-2x=-22

x=-22/-2

x=+11

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