(x-4)(x+5)=(x+1)(x-5)

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Solution for (x-4)(x+5)=(x+1)(x-5) equation: 



(x-4)(x+5)=(x+1)(x-5)

We move all terms to the left:

(x-4)(x+5)-((x+1)(x-5))=0

We multiply parentheses ..

(+x^2+5x-4x-20)-((x+1)(x-5))=0



We calculate terms in parentheses: -((x+1)(x-5)), so:

(x+1)(x-5)

We multiply parentheses ..

(+x^2-5x+x-5)

We get rid of parentheses

x^2-5x+x-5

We add all the numbers together, and all the variables

x^2-4x-5

Back to the equation:

-(x^2-4x-5)



We get rid of parentheses

x^2-x^2+5x-4x+4x-20+5=0

We add all the numbers together, and all the variables

5x-15=0

We move all terms containing x to the left, all other terms to the right

5x=15

x=15/5

x=3

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