(x-4)(x+6)-2(11x-62)=0

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Solution for (x-4)(x+6)-2(11x-62)=0 equation: 



(x-4)(x+6)-2(11x-62)=0

We multiply parentheses

(x-4)(x+6)-22x+124=0

We multiply parentheses ..

(+x^2+6x-4x-24)-22x+124=0

We get rid of parentheses

x^2+6x-4x-22x-24+124=0

We add all the numbers together, and all the variables

x^2-20x+100=0

a = 1; b = -20; c = +100;
Δ = b2-4ac
Δ = -202-4·1·100
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{20}{2}=10$

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