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(x-4)(x-2)=x-6x
We move all terms to the left:
(x-4)(x-2)-(x-6x)=0
We add all the numbers together, and all the variables
(x-4)(x-2)-(-5x)=0
We get rid of parentheses
(x-4)(x-2)+5x=0
We multiply parentheses ..
(+x^2-2x-4x+8)+5x=0
We get rid of parentheses
x^2-2x-4x+5x+8=0
We add all the numbers together, and all the variables
x^2-1x+8=0
a = 1; b = -1; c = +8;
Δ = b2-4ac
Δ = -12-4·1·8
Δ = -31
Delta is less than zero, so there is no solution for the equation
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