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(x-4)(x-2)=x-8
We move all terms to the left:
(x-4)(x-2)-(x-8)=0
We get rid of parentheses
(x-4)(x-2)-x+8=0
We multiply parentheses ..
(+x^2-2x-4x+8)-x+8=0
We add all the numbers together, and all the variables
(+x^2-2x-4x+8)-1x+8=0
We get rid of parentheses
x^2-2x-4x-1x+8+8=0
We add all the numbers together, and all the variables
x^2-7x+16=0
a = 1; b = -7; c = +16;
Δ = b2-4ac
Δ = -72-4·1·16
Δ = -15
Delta is less than zero, so there is no solution for the equation
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