(x-4)(x-3)(x-2)(x-1)=120

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Solution for (x-4)(x-3)(x-2)(x-1)=120 equation: 



(x-4)(x-3)(x-2)(x-1)=120

We move all terms to the left:

(x-4)(x-3)(x-2)(x-1)-(120)=0

We multiply parentheses ..

(+x^2-3x-4x+12)(x-2)(x-1)-120=0

We multiply parentheses ..

(+x^2-3x-4x+12)(+x^2-1x-2x+2)-120=0

We move all terms containing x to the left, all other terms to the right

(+x^2-3x-4x+12)(+x^2-1x-2x+2)=120

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