(x-4)(x-4)-1=(x-3)(x-2)

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Solution for (x-4)(x-4)-1=(x-3)(x-2) equation: 



(x-4)(x-4)-1=(x-3)(x-2)

We move all terms to the left:

(x-4)(x-4)-1-((x-3)(x-2))=0

We multiply parentheses ..

(+x^2-4x-4x+16)-((x-3)(x-2))-1=0



We calculate terms in parentheses: -((x-3)(x-2)), so:

(x-3)(x-2)

We multiply parentheses ..

(+x^2-2x-3x+6)

We get rid of parentheses

x^2-2x-3x+6

We add all the numbers together, and all the variables

x^2-5x+6

Back to the equation:

-(x^2-5x+6)



We get rid of parentheses

x^2-x^2-4x-4x+5x+16-6-1=0

We add all the numbers together, and all the variables

-3x+9=0

We move all terms containing x to the left, all other terms to the right

-3x=-9

x=-9/-3

x=+3

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