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(x-4)(x-4)-1=(x-3)(x-2)
We move all terms to the left:
(x-4)(x-4)-1-((x-3)(x-2))=0
We multiply parentheses ..
(+x^2-4x-4x+16)-((x-3)(x-2))-1=0
We calculate terms in parentheses: -((x-3)(x-2)), so:We get rid of parentheses
(x-3)(x-2)
We multiply parentheses ..
(+x^2-2x-3x+6)
We get rid of parentheses
x^2-2x-3x+6
We add all the numbers together, and all the variables
x^2-5x+6
Back to the equation:
-(x^2-5x+6)
x^2-x^2-4x-4x+5x+16-6-1=0
We add all the numbers together, and all the variables
-3x+9=0
We move all terms containing x to the left, all other terms to the right
-3x=-9
x=-9/-3
x=+3
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