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(x-4)(x-4)-5x=0
We add all the numbers together, and all the variables
-5x+(x-4)(x-4)=0
We multiply parentheses ..
(+x^2-4x-4x+16)-5x=0
We get rid of parentheses
x^2-4x-4x-5x+16=0
We add all the numbers together, and all the variables
x^2-13x+16=0
a = 1; b = -13; c = +16;
Δ = b2-4ac
Δ = -132-4·1·16
Δ = 105
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-\sqrt{105}}{2*1}=\frac{13-\sqrt{105}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+\sqrt{105}}{2*1}=\frac{13+\sqrt{105}}{2} $
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