(x-4)(x-4)=(x+3)(x-3)

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Solution for (x-4)(x-4)=(x+3)(x-3) equation: 



(x-4)(x-4)=(x+3)(x-3)

We move all terms to the left:

(x-4)(x-4)-((x+3)(x-3))=0

We use the square of the difference formula

x^2+(x-4)(x-4)+9=0

We multiply parentheses ..

x^2+(+x^2-4x-4x+16)+9=0

We get rid of parentheses

x^2+x^2-4x-4x+16+9=0

We add all the numbers together, and all the variables

2x^2-8x+25=0

a = 2; b = -8; c = +25;
Δ = b2-4ac
Δ = -82-4·2·25
Δ = -136
Delta is less than zero, so there is no solution for the equation

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