(x-4)(x-5)(x-6)(x-7)-24=0

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Solution for (x-4)(x-5)(x-6)(x-7)-24=0 equation:



(x-4)(x-5)(x-6)(x-7)-24=0
We multiply parentheses ..
(+x^2-5x-4x+20)(x-6)(x-7)-24=0
We multiply parentheses ..
(+x^2-5x-4x+20)(+x^2-7x-6x+42)-24=0
We move all terms containing x to the left, all other terms to the right
(+x^2-5x-4x+20)(+x^2-7x-6x+42)=24

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