(x-4)(x-5)(x-6)(x-7)=1690

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Solution for (x-4)(x-5)(x-6)(x-7)=1690 equation: 



(x-4)(x-5)(x-6)(x-7)=1690

We move all terms to the left:

(x-4)(x-5)(x-6)(x-7)-(1690)=0

We multiply parentheses ..

(+x^2-5x-4x+20)(x-6)(x-7)-1690=0

We multiply parentheses ..

(+x^2-5x-4x+20)(+x^2-7x-6x+42)-1690=0

We move all terms containing x to the left, all other terms to the right

(+x^2-5x-4x+20)(+x^2-7x-6x+42)=1690

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