(x-4)+(4x+16)+x=(x-4)+(4x+16)+x

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Solution for (x-4)+(4x+16)+x=(x-4)+(4x+16)+x equation:



(x-4)+(4x+16)+x=(x-4)+(4x+16)+x
We move all terms to the left:
(x-4)+(4x+16)+x-((x-4)+(4x+16)+x)=0
We add all the numbers together, and all the variables
x+(x-4)+(4x+16)-((x-4)+(4x+16)+x)=0
We get rid of parentheses
x+x+4x-((x-4)+(4x+16)+x)-4+16=0
We calculate terms in parentheses: -((x-4)+(4x+16)+x), so:
(x-4)+(4x+16)+x
We add all the numbers together, and all the variables
x+(x-4)+(4x+16)
We get rid of parentheses
x+x+4x-4+16
We add all the numbers together, and all the variables
6x+12
Back to the equation:
-(6x+12)
We add all the numbers together, and all the variables
6x-(6x+12)+12=0
We get rid of parentheses
6x-6x-12+12=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0

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