(x-4)+(4x+16)+x=(x-4)+(4x+16)+x

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Solution for (x-4)+(4x+16)+x=(x-4)+(4x+16)+x equation: 



(x-4)+(4x+16)+x=(x-4)+(4x+16)+x

We move all terms to the left:

(x-4)+(4x+16)+x-((x-4)+(4x+16)+x)=0

We add all the numbers together, and all the variables

x+(x-4)+(4x+16)-((x-4)+(4x+16)+x)=0

We get rid of parentheses

x+x+4x-((x-4)+(4x+16)+x)-4+16=0



We calculate terms in parentheses: -((x-4)+(4x+16)+x), so:

(x-4)+(4x+16)+x

We add all the numbers together, and all the variables

x+(x-4)+(4x+16)

We get rid of parentheses

x+x+4x-4+16

We add all the numbers together, and all the variables

6x+12

Back to the equation:

-(6x+12)



We add all the numbers together, and all the variables

6x-(6x+12)+12=0

We get rid of parentheses

6x-6x-12+12=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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