(x-4)+(x-3)+x=40

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Solution for (x-4)+(x-3)+x=40 equation: 



(x-4)+(x-3)+x=40

We move all terms to the left:

(x-4)+(x-3)+x-(40)=0

We add all the numbers together, and all the variables

x+(x-4)+(x-3)-40=0

We get rid of parentheses

x+x+x-4-3-40=0

We add all the numbers together, and all the variables

3x-47=0

We move all terms containing x to the left, all other terms to the right

3x=47

x=47/3

x=15+2/3

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