(x-4)+(x-4*3/2x)=2x*2x

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Solution for (x-4)+(x-4*3/2x)=2x*2x equation: 



(x-4)+(x-4*3/2x)=2x*2x

We move all terms to the left:

(x-4)+(x-4*3/2x)-(2x*2x)=0



Domain of the equation: 2x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(x-4)+(+x-4*3/2x)-(+2x*2x)=0

We get rid of parentheses

x+x-4*3/2x-2x*2x-4=0

We multiply all the terms by the denominator


x*2x+x*2x-(2x*2x)*2x-4*2x-4*3=0

We add all the numbers together, and all the variables

x*2x+x*2x-(+2x*2x)*2x-4*2x-4*3=0

We add all the numbers together, and all the variables

x*2x+x*2x-(+2x*2x)*2x-4*2x-12=0

We multiply parentheses

-8x^3+x*2x+x*2x-4*2x-12=0

Wy multiply elements

-8x^3+2x^2+2x^2-8x-12=0

We do not support expression: x^3

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