(x-4)+15=2(x+5)

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Solution for (x-4)+15=2(x+5) equation: 



(x-4)+15=2(x+5)

We move all terms to the left:

(x-4)+15-(2(x+5))=0

We get rid of parentheses

x-(2(x+5))-4+15=0



We calculate terms in parentheses: -(2(x+5)), so:

2(x+5)

We multiply parentheses

2x+10

Back to the equation:

-(2x+10)



We add all the numbers together, and all the variables

x-(2x+10)+11=0

We get rid of parentheses

x-2x-10+11=0

We add all the numbers together, and all the variables

-1x+1=0

We move all terms containing x to the left, all other terms to the right

-x=-1

x=-1/-1

x=1

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