(x-4)+15=2(x+5)

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Solution for (x-4)+15=2(x+5) equation:



(x-4)+15=2(x+5)
We move all terms to the left:
(x-4)+15-(2(x+5))=0
We get rid of parentheses
x-(2(x+5))-4+15=0
We calculate terms in parentheses: -(2(x+5)), so:
2(x+5)
We multiply parentheses
2x+10
Back to the equation:
-(2x+10)
We add all the numbers together, and all the variables
x-(2x+10)+11=0
We get rid of parentheses
x-2x-10+11=0
We add all the numbers together, and all the variables
-1x+1=0
We move all terms containing x to the left, all other terms to the right
-x=-1
x=-1/-1
x=1

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