(x-4)-(4x+1)=2(3x+4)-(6x-2)

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Solution for (x-4)-(4x+1)=2(3x+4)-(6x-2) equation: 



(x-4)-(4x+1)=2(3x+4)-(6x-2)

We move all terms to the left:

(x-4)-(4x+1)-(2(3x+4)-(6x-2))=0

We get rid of parentheses

x-4x-(2(3x+4)-(6x-2))-4-1=0



We calculate terms in parentheses: -(2(3x+4)-(6x-2)), so:

2(3x+4)-(6x-2)

We multiply parentheses

6x-(6x-2)+8

We get rid of parentheses

6x-6x+2+8

We add all the numbers together, and all the variables

10

Back to the equation:

-(10)



We add all the numbers together, and all the variables

-3x-15=0

We move all terms containing x to the left, all other terms to the right

-3x=15

x=15/-3

x=-5

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