(x-4)-5=(17-x)-5

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Solution for (x-4)-5=(17-x)-5 equation: 



(x-4)-5=(17-x)-5

We move all terms to the left:

(x-4)-5-((17-x)-5)=0

We add all the numbers together, and all the variables

(x-4)-((-1x+17)-5)-5=0

We get rid of parentheses

x-((-1x+17)-5)-4-5=0



We calculate terms in parentheses: -((-1x+17)-5), so:

(-1x+17)-5

We get rid of parentheses

-1x+17-5

We add all the numbers together, and all the variables

-1x+12

Back to the equation:

-(-1x+12)



We add all the numbers together, and all the variables

x-(-1x+12)-9=0

We get rid of parentheses

x+1x-12-9=0

We add all the numbers together, and all the variables

2x-21=0

We move all terms containing x to the left, all other terms to the right

2x=21

x=21/2

x=10+1/2

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