(x-4)/(7)=(8-3x)/(5)

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Solution for (x-4)/(7)=(8-3x)/(5) equation:



(x-4)/(7)=(8-3x)/(5)
We move all terms to the left:
(x-4)/(7)-((8-3x)/(5))=0
We add all the numbers together, and all the variables
(x-4)/7-((-3x+8)/5)=0
We calculate fractions
x/()+(-((-3x+8)*7)/()=0
We calculate terms in parentheses: +(-((-3x+8)*7)/(), so:
-((-3x+8)*7)/(
We multiply all the terms by the denominator
-((-3x+8)*7)
We calculate terms in parentheses: -((-3x+8)*7), so:
(-3x+8)*7
We multiply parentheses
-21x+56
Back to the equation:
-(-21x+56)
We get rid of parentheses
21x-56
Back to the equation:
+(21x-56)
We get rid of parentheses
x/()+21x-56=0
We multiply all the terms by the denominator
x+21x*()-56*()=0
We add all the numbers together, and all the variables
x+21x*()=0

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