(x-4)/(7)=(8-3x)/(5)

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Solution for (x-4)/(7)=(8-3x)/(5) equation: 



(x-4)/(7)=(8-3x)/(5)

We move all terms to the left:

(x-4)/(7)-((8-3x)/(5))=0

We add all the numbers together, and all the variables

(x-4)/7-((-3x+8)/5)=0

We calculate fractions


x/()+(-((-3x+8)*7)/()=0



We calculate terms in parentheses: +(-((-3x+8)*7)/(), so:

-((-3x+8)*7)/(

We multiply all the terms by the denominator


-((-3x+8)*7)



We calculate terms in parentheses: -((-3x+8)*7), so:

(-3x+8)*7

We multiply parentheses

-21x+56

Back to the equation:

-(-21x+56)



We get rid of parentheses

21x-56

Back to the equation:

+(21x-56)



We get rid of parentheses

x/()+21x-56=0

We multiply all the terms by the denominator


x+21x*()-56*()=0

We add all the numbers together, and all the variables

x+21x*()=0

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