(x-4)/2=(2-x)/3

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Solution for (x-4)/2=(2-x)/3 equation: 



(x-4)/2=(2-x)/3

We move all terms to the left:

(x-4)/2-((2-x)/3)=0

We add all the numbers together, and all the variables

(x-4)/2-((-1x+2)/3)=0

We calculate fractions


x/()+(-((-1x+2)*2)/()=0



We calculate terms in parentheses: +(-((-1x+2)*2)/(), so:

-((-1x+2)*2)/(

We multiply all the terms by the denominator


-((-1x+2)*2)



We calculate terms in parentheses: -((-1x+2)*2), so:

(-1x+2)*2

We multiply parentheses

-2x+4

Back to the equation:

-(-2x+4)



We get rid of parentheses

2x-4

Back to the equation:

+(2x-4)



We get rid of parentheses

x/()+2x-4=0

We multiply all the terms by the denominator


x+2x*()-4*()=0

We add all the numbers together, and all the variables

x+2x*()=0

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