(x-4)/3=(x+1)/2

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Solution for (x-4)/3=(x+1)/2 equation:



(x-4)/3=(x+1)/2
We move all terms to the left:
(x-4)/3-((x+1)/2)=0
We calculate fractions
x/()+(-((x+1)*3)/()=0
We calculate terms in parentheses: +(-((x+1)*3)/(), so:
-((x+1)*3)/(
We multiply all the terms by the denominator
-((x+1)*3)
We calculate terms in parentheses: -((x+1)*3), so:
(x+1)*3
We multiply parentheses
3x+3
Back to the equation:
-(3x+3)
We get rid of parentheses
-3x-3
Back to the equation:
+(-3x-3)
We get rid of parentheses
x/()-3x-3=0
We multiply all the terms by the denominator
x-3x*()-3*()=0
We add all the numbers together, and all the variables
x-3x*()=0

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