(x-4)/5=9-(2x-4)/9

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Solution for (x-4)/5=9-(2x-4)/9 equation: 



(x-4)/5=9-(2x-4)/9

We move all terms to the left:

(x-4)/5-(9-(2x-4)/9)=0

We calculate fractions


x/()+(-(9-(2x-4)*5)/()=0



We calculate terms in parentheses: +(-(9-(2x-4)*5)/(), so:

-(9-(2x-4)*5)/(

We multiply all the terms by the denominator


-(9-(2x-4)*5)



We calculate terms in parentheses: -(9-(2x-4)*5), so:

9-(2x-4)*5

determiningTheFunctionDomain
-(2x-4)*5+9

We multiply parentheses

-10x+20+9

We add all the numbers together, and all the variables

-10x+29

Back to the equation:

-(-10x+29)



We get rid of parentheses

10x-29

Back to the equation:

+(10x-29)



We get rid of parentheses

x/()+10x-29=0

We multiply all the terms by the denominator


x+10x*()-29*()=0

We add all the numbers together, and all the variables

x+10x*()=0

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