(x-4)/8=(x-3)/10

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Solution for (x-4)/8=(x-3)/10 equation: 



(x-4)/8=(x-3)/10

We move all terms to the left:

(x-4)/8-((x-3)/10)=0

We calculate fractions


x/()+(-((x-3)*8)/()=0



We calculate terms in parentheses: +(-((x-3)*8)/(), so:

-((x-3)*8)/(

We multiply all the terms by the denominator


-((x-3)*8)



We calculate terms in parentheses: -((x-3)*8), so:

(x-3)*8

We multiply parentheses

8x-24

Back to the equation:

-(8x-24)



We get rid of parentheses

-8x+24

Back to the equation:

+(-8x+24)



We get rid of parentheses

x/()-8x+24=0

We multiply all the terms by the denominator


x-8x*()+24*()=0

We add all the numbers together, and all the variables

x-8x*()=0

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