(x-4)/9=(x+3)/5

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Solution for (x-4)/9=(x+3)/5 equation: 



(x-4)/9=(x+3)/5

We move all terms to the left:

(x-4)/9-((x+3)/5)=0

We calculate fractions


x/()+(-((x+3)*9)/()=0



We calculate terms in parentheses: +(-((x+3)*9)/(), so:

-((x+3)*9)/(

We multiply all the terms by the denominator


-((x+3)*9)



We calculate terms in parentheses: -((x+3)*9), so:

(x+3)*9

We multiply parentheses

9x+27

Back to the equation:

-(9x+27)



We get rid of parentheses

-9x-27

Back to the equation:

+(-9x-27)



We get rid of parentheses

x/()-9x-27=0

We multiply all the terms by the denominator


x-9x*()-27*()=0

We add all the numbers together, and all the variables

x-9x*()=0

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