(x-4)2+(y+3)2=20

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Solution for (x-4)2+(y+3)2=20 equation: 


Simplifying
(x + -4) * 2 + (y + 3) * 2 = 20

Reorder the terms:
(-4 + x) * 2 + (y + 3) * 2 = 20

Reorder the terms for easier multiplication:
2(-4 + x) + (y + 3) * 2 = 20
(-4 * 2 + x * 2) + (y + 3) * 2 = 20
(-8 + 2x) + (y + 3) * 2 = 20

Reorder the terms:
-8 + 2x + (3 + y) * 2 = 20

Reorder the terms for easier multiplication:
-8 + 2x + 2(3 + y) = 20
-8 + 2x + (3 * 2 + y * 2) = 20
-8 + 2x + (6 + 2y) = 20

Reorder the terms:
-8 + 6 + 2x + 2y = 20

Combine like terms: -8 + 6 = -2
-2 + 2x + 2y = 20

Solving
-2 + 2x + 2y = 20

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 2x + 2 + 2y = 20 + 2

Reorder the terms:
-2 + 2 + 2x + 2y = 20 + 2

Combine like terms: -2 + 2 = 0
0 + 2x + 2y = 20 + 2
2x + 2y = 20 + 2

Combine like terms: 20 + 2 = 22
2x + 2y = 22

Add '-2y' to each side of the equation.
2x + 2y + -2y = 22 + -2y

Combine like terms: 2y + -2y = 0
2x + 0 = 22 + -2y
2x = 22 + -2y

Divide each side by '2'.
x = 11 + -1y

Simplifying
x = 11 + -1y

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