(x-4)x=(x)x-(4)x=x2-4x

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Solution for (x-4)x=(x)x-(4)x=x2-4x equation: 



(x-4)x=(x)x-(4)x=x2-4x

We move all terms to the left:

(x-4)x-((x)x-(4)x)=0

We add all the numbers together, and all the variables

(x-4)x-(-4x+xx)=0

We multiply parentheses

x^2-4x-(-4x+xx)=0

We get rid of parentheses

x^2-4x+4x-xx=0

We add all the numbers together, and all the variables

x^2-xx=0

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