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(x-4)x=165
We move all terms to the left:
(x-4)x-(165)=0
We multiply parentheses
x^2-4x-165=0
a = 1; b = -4; c = -165;
Δ = b2-4ac
Δ = -42-4·1·(-165)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{676}=26$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-26}{2*1}=\frac{-22}{2} =-11 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+26}{2*1}=\frac{30}{2} =15 $
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