(x-4/4)-1=(x-12/5)

Solution for (x-4/4)-1=(x-12/5) equation:

(x-4/4)-1=(x-12/5)

We move all terms to the left:

(x-4/4)-1-((x-12/5))=0

We add all the numbers together, and all the variables

(x-1)-((+x-12/5))-1=0

We get rid of parentheses

x-((+x-12/5))-1-1=0

We multiply all the terms by the denominator


x*5))-((+x-12-1*5))-1*5))=0

We add all the numbers together, and all the variables

x*5))-((x-17))-1*5))=0

We add all the numbers together, and all the variables

x*5))-((x=0

Wy multiply elements

5x^2=0

a = 5; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·5·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{10}=0$