(x-4/x+2)=(x+1/x+3)+1

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Solution for (x-4/x+2)=(x+1/x+3)+1 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

x-(4/x)+2 = x+1/x+1+3 // - x+1/x+1+3

x-x-(4/x)-(1/x)-3-1+2 = 0

x-x-4*x^-1-x^-1-3-1+2 = 0

-5*x^-1 = 2 // : -5

x^-1 = -2/5

-1 < 0

1/(x^1) = -2/5 // * x^1

1 = -2/5*x^1 // : -2/5

-5/2 = x^1

x = -5/2

x = -5/2

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