(x-4/x2)+(2x-5-2x/x2-4)=2/x2-2x

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Solution for (x-4/x2)+(2x-5-2x/x2-4)=2/x2-2x equation: 



(x-4/x2)+(2x-5-2x/x2-4)=2/x2-2x

We move all terms to the left:

(x-4/x2)+(2x-5-2x/x2-4)-(2/x2-2x)=0



Domain of the equation: x2)!=0

x!=0/1

x!=0

x∈R





Domain of the equation: x2-4)!=0

x∈R





Domain of the equation: x2-2x)!=0

x∈R



We add all the numbers together, and all the variables

(+x-4/x2)+(2x-2x/x2-9)-(-2x+2/x2)=0

We get rid of parentheses

x-4/x2+2x-2x/x2+2x-2/x2-9=0

We multiply all the terms by the denominator


x*x2+2x*x2-2x+2x*x2-9*x2-4-2=0

We add all the numbers together, and all the variables

-9x^2-2x+x*x2+2x*x2+2x*x2-6=0

Wy multiply elements

-9x^2+x^3+2x^3+2x^3-2x-6=0

We do not support expression: x^3

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