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(x-47)(x+11)=0
We multiply parentheses ..
(+x^2+11x-47x-517)=0
We get rid of parentheses
x^2+11x-47x-517=0
We add all the numbers together, and all the variables
x^2-36x-517=0
a = 1; b = -36; c = -517;
Δ = b2-4ac
Δ = -362-4·1·(-517)
Δ = 3364
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3364}=58$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-58}{2*1}=\frac{-22}{2} =-11 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+58}{2*1}=\frac{94}{2} =47 $
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