(x-48)(8x+7)=0

Solution for (x-48)(8x+7)=0 equation:

(x-48)(8x+7)=0

We multiply parentheses ..

(+8x^2+7x-384x-336)=0

We get rid of parentheses

8x^2+7x-384x-336=0

We add all the numbers together, and all the variables

8x^2-377x-336=0

a = 8; b = -377; c = -336;
Δ = b2-4ac
Δ = -3772-4·8·(-336)
Δ = 152881
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{152881}=391$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-377)-391}{2*8}=\frac{-14}{16}
=-7/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-377)+391}{2*8}=\frac{768}{16}
=48
$