(x-5)(2x-7)+49=0

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Solution for (x-5)(2x-7)+49=0 equation: 



(x-5)(2x-7)+49=0

We multiply parentheses ..

(+2x^2-7x-10x+35)+49=0

We get rid of parentheses

2x^2-7x-10x+35+49=0

We add all the numbers together, and all the variables

2x^2-17x+84=0

a = 2; b = -17; c = +84;
Δ = b2-4ac
Δ = -172-4·2·84
Δ = -383
Delta is less than zero, so there is no solution for the equation

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